Find the largest 4-digit number when divided by 40,48,60 leaves remainder 3 in each case. Question Find the largest 4-digit number when divided by 40,48,60 leaves remainder 3 in each case. in progress 0 Math Melody 1 week 2021-10-04T21:39:51+00:00 2021-10-04T21:39:51+00:00 2 Answers 0 views 0

## Answers ( )

SOLUTION :Firstly, we get L.C.M of 40,48 & 60.

∴ L.C.M = 2 × 2 × 2 × 2 × 3 × 5 =

240Now,

We know greatest four digit =

9999240) 9999( 41

960

______________

399

240

_______________

159

_______________

∴ 9999 – 159 =

9840which is divisible.Thus;

The required number = 9840 – 3 =

9837Answer:YOURANSWERISHERE:A.9996isdivisiblebyall3number.Step-by-step explanation:A. The greatest four digit number is 9999 .

Now find the HCF of 40 , 48 , 60 –

40 = 2 × 2 × 5

48 = 2 × 2 × 2 × 2 × 3

60 = 2 × 2 × 3 × 5

HCF = 4

Divide 9999 by 4

9999 ÷ 4 = 2499 and remainder is 3

2499 × 4 + 3

9999 – 3 = 9996

Theansweris9996andthenumbersremainderis3.PLEASEMARKME ASBRAINLIST.